New User ? Sign Up  |  Sign In  |  Help
ask
Ask whatever question, you wish. Make sure you select the correct category for the question.
answer
Like to help other, then browse through the open questions to answer their questions.
discover
Find answer by browsing the resolved questions.
     
Search for questions :
My Profile

Sydney

Open Question Bookmark and Share

General Chem question?

Given 0.1 M solutions of acetic acid and sodium acetate, describe the preparation of 1 L of 0.1 M acetate buffer at pH 5.4

513 day(s) ago

    Comment(s) (0)
    Report Abuse
   Find Intereseting  
   E-Mail to Friends  
   Bookmark  
   Subscribe to Answer Alert  
No comments yet !!!     Be the first to comment
Answers (1)

jerry87384 		pKa = 4.7
5.4 - 4.7 =0.7
10^0.7=5.0 = [CH3COO-]/ [CH3COOH]

[CH3COOH]+[CH3COO-] = 0.1

x + y = 0.1
5.0 = y/x

5.0 x = y
6.0 x = 0.1
x = 0.0167 M = [acetic acid]
y = 0.0833 M = [acetate]

moles acetic acid = 0.0167
moles acetate = 0.0833

multiply by the molar mass to get the mass

Posted 513 days ago

( 0 )
( 0 )
    Comment(s) (0)
   Report Abuse
No comments yet !!! Be the first to comment on this answer !!!

Edit your answer. Click save, when done.
Question Title General Chem question?
Your Answer
Character Count ( Max. - 5000 ) : 123
Email this question link to friends
You must enter email-address, if name is entered and vice-versa for each friend.
Friend #1 -
Friend #2 -
Friend #3 -
Friend #4 -
Friend #5 -
  Your comment on this question
Max Allowed : 5000 Characters Current Count : 0
  Your comment on this answer
Max Allowed : 5000 Characters Current Count : 0